没有样式就是最好的样式
运行下面代码可知。opera,IE都支持这两个方法(对象),mozilla(firefox)不支持。对于 children可以用 childNode() 来解决。
a.contains(b) 返回 a 节点中是否包含 b。
var x = document.getElementById('writeroot'); var y = document.getElementById('test'); alert(x.contains(y)); alert(y.contains(x)); alert(x.children.length) [Ctrl+A 全部选择 提示:你可先修改部分代码,再按运行]
var x = document.getElementById('writeroot');
var y = document.getElementById('test');
alert(x.contains(y));
alert(y.contains(x));
alert(x.children.length)
quirksmode说是可以用 compareDocumentPosition() 来处理,但我测试目前浏览器都不行。
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